For \(\alpha, \beta, z \in C\) and \(\lambda>1\), if \(\sqrt{\lambda-1}\) is the radius of th.... VIDEO
For \(\alpha, \beta, z \in C\) and \(\lambda>1\), if \(\sqrt{\lambda-1}\) is the radius of the circle \(|z-\alpha|^2+|z-\beta|^2=2 \lambda\), then \(|\alpha-\beta|\) is equal to 📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live
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