If \( (4+\sqrt{15})^{n}=I+f \), where \( n \) is an odd natural number, \( I \) is an integer an... VIDEO
If \( (4+\sqrt{15})^{n}=I+f \), where \( n \) is an odd natural number, \( I \) is an integer and \( 0f1 \), then
(1) \( I \) is an odd integer
(2) \( I \) is an even integer
(3) \( (I+f)(1-f)=1 \)
(4) \( 1-f=(4-\sqrt{15})^{n} \)
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