If an electron is revolving around the nucleus of \( \mathrm{He}^{+} \)ion at a distance of \( 4...
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If an electron is revolving around the nucleus of \( \mathrm{He}^{+} \)ion at a distance of \( 4.0 \AA \), the magnitude of centripetal force on electron by the nucleus is \( (e= \) \( \left.1.6 \times 10^{-19} \mathrm{C}\right) \)
(a) \( 2.88 \times 10^{-9} \mathrm{~N} \)
(b) \( 2.88 \times 10^{-7} \mathrm{~N} \)
(c) \( 1.152 \times 10^{-18} \mathrm{~N} \)
(d) \( 1.44 \times 10^{-9} \mathrm{~N} \)
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