If \( \frac{1+\sin \alpha}{1-\sin \alpha}=\frac{m^{2}}{n^{2}} \), then \( \sin \alpha \) is (a) ...

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If \( \frac{1+\sin \alpha}{1-\sin \alpha}=\frac{m^{2}}{n^{2}} \), then \( \sin \alpha \) is
(a) \( \frac{m^{2}+n^{2}}{m^{2}-n^{2}} \)
(b) \( \frac{m^{2}-n^{2}}{m^{2}+n^{2}} \)
(c) \( \frac{m^{2}+n^{2}}{n^{2}-m^{2}} \)
(d) \( \frac{n^{2}-m^{2}}{m^{2}+n^{2}} \)
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