If \( I_{1}=\int_{1-k}^{k} x \sin (x(1-x)) d x \) and \( I_{2}=\int_{1 \div k}^{k} \sin (x(1-x))...
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If \( I_{1}=\int_{1-k}^{k} x \sin (x(1-x)) d x \) and \( I_{2}=\int_{1 \div k}^{k} \sin (x(1-x)) d x \) then
(A) \( I_{1}=2 I_{2} \)
(B) \( 2 I_{1}=I_{2} \)
(C) \( I_{1}=I_{2} \)
(D) none of these
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