If \( \lambda_{\mathrm{Cu}} \) is the wavelength of \( K_{\alpha} \mathrm{x} \)-ray line of copp...
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0If \( \lambda_{\mathrm{Cu}} \) is the wavelength of \( K_{\alpha} \mathrm{x} \)-ray line of copper (atomic number 29) and \( \lambda_{\mathrm{Mo}_{0}} \) is the wavelength of the \( K_{\alpha} \mathrm{x} \)-ray line of molybdenum (atomic number 42 ), then the ratio \( \lambda_{\mathrm{Cu}} / \) \( \lambda_{\mathrm{Mo}} \) is close to
(A) \( 1.9 \)
(B) \( 2.14 \)
(C) \( 0.50 \)
(D) \( 0.48 \)
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