If \( \log _{10} 2=0.30103, \log _{10} 3=0.47712 \), the number of digits in \( 3^{12} \times 2^... VIDEO
If \( \log _{10} 2=0.30103, \log _{10} 3=0.47712 \), the number of digits in \( 3^{12} \times 2^{8} \) is
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(i) \( (2 \sqrt{3}-5 \sqrt{2}) \) and \( (\sqrt{3}+2 \sqrt{2}) \)
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(a) 4
(b) \( \frac{17}{4} \)
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