If \( (\sec \theta-1)=(\sqrt{2}-1) \tan \theta \), then \( \theta= \) (A) \( n \pi+\frac{\pi}{8}...

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If \( (\sec \theta-1)=(\sqrt{2}-1) \tan \theta \), then \( \theta= \)
(A) \( n \pi+\frac{\pi}{8}, n \in Z \)
(B) \( 2 n \pi, 2 n \pi+\frac{\pi}{4}, n \in Z \)
(C) \( 2 n \pi, n \in Z \)
(D) none of these
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