If the line \( 2 x+\sqrt{6} y=2 \) touches the hyperbola \( x^{2}-2 y^{2}=4 \), then the point o....
Channel:
Subscribers:
445,000
Published on ● Video Link: https://www.youtube.com/watch?v=Eg5SawmQMEc
If the line \( 2 x+\sqrt{6} y=2 \) touches the hyperbola
\( \mathrm{P} \)
\( x^{2}-2 y^{2}=4 \), then the point of contact is
(1) \( (-2, \sqrt{6}) \)
(2) \( (-5,2 \sqrt{6}) \)
(3) \( \left(\frac{1}{2}, \frac{1}{\sqrt{6}}\right) \)
(4) \( (4,-\sqrt{6}) \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live