If the reflection of the ellipse \( \frac{(x-4)^{2}}{16}+\frac{(y-3)^{2}}{9}=1 \) in the mirror ...

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If the reflection of the ellipse \( \frac{(x-4)^{2}}{16}+\frac{(y-3)^{2}}{9}=1 \) in the mirror line \( x-y-2=0 \) is \( k_{1} x^{2}+k_{2} y^{2}-160 x-36 y+292= \) 0 , then \( \frac{k_{1}+k_{2}}{5} \) is equal to
(a) 4
(b) 5
(c) 6
(d) 7
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