If \( x_{1}=3 \) and \( x_{n+1}=\sqrt{2+x_{n}}, n \geq 1 \), then \( \lim _{n \rightarrow \infty...
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If \( x_{1}=3 \) and \( x_{n+1}=\sqrt{2+x_{n}}, n \geq 1 \), then \( \lim _{n \rightarrow \infty} x_{n} \) is equal to
(A) \( -1 \)
(B) 2
(C) \( \sqrt{5} \)
(D) 3
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