If \(x^{p}y^{q} = (x + y)^{p + q}\), prove that \(\frac{\text{dy}}{\text{dx}} = \frac{y}{x}\)....
If \(x^{p}y^{q} = (x + y)^{p + q}\), prove that \(\frac{\text{dy}}{\text{dx}} = \frac{y}{x}\)....
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