If \( y=\left(\frac{2}{\pi} x-1\right) \operatorname{cosec} x \) is...

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If \( y=\left(\frac{2}{\pi} x-1\right) \operatorname{cosec} x \) is the solution of the differential
\( \mathrm{P} \) equation, \( \frac{d y}{d x}+p(x) y=\frac{2}{\pi} \operatorname{cosec} x, 0x\frac{\pi}{2} \), then the function \( p(x) \) is equal to:
(a) \( \tan x \)
[JEE Main-2020 (September)]
(c) \( \operatorname{cosec} x \)
(b) \( \cot x \)
(d) \( \sec x \)
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