If \( y=\log _{a} x+\log _{x} a+\log _{x} x+\log _{a} a \), then \( \frac{d y}{d x} \) is equal to

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If \( y=\log _{a} x+\log _{x} a+\log _{x} x+\log _{a} a \), then \( \frac{d y}{d x} \) is equal to
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