If \(y=y(x)\) is the solution of the differential equation \(x \frac{d y}{d x}+2 y=x e^x, y(1)=0....

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If \(y=y(x)\) is the solution of the differential equation \(x \frac{d y}{d x}+2 y=x e^x, y(1)=0\) then the local maximum value of the function \(z(x)=x^2 y(x)-e x, x \in R\) is: šŸ“²PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live




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