In a \( \triangle A B C \frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4 b^{2} c^{2}} \) equals (A) \( \cos...
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0In a \( \triangle A B C \frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4 b^{2} c^{2}} \) equals
(A) \( \cos ^{2} A \)
(B) \( \sin ^{2} A \)
(C) \( \cos ^{2} B \)
(D) \( \sin ^{2} B \)
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