In a workshop, there are five machines and the probability of any one of them to be out of servi... VIDEO
In a workshop, there are five machines and the probability of any one of them to be out of service on a day is \( \frac{1}{4} \). If the probability that at most two machines will be out of service on the same
\( \mathrm{P} \) day is \( \left(\frac{3}{4}\right)^{3} \mathrm{k} \), then \( \mathrm{k} \) is equal to :
(1) \( \frac{17}{2} \)
(2) 4
(3) \( \frac{17}{8} \)
(4) \( \frac{17}{4} \)
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