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In the circuit shown in Fi\& initially key \( \mathrm{K}_{1} \) is closed and key \( \mathrm{K}_{2} \) is open. Then \( \mathrm{K}_{1} \) is opened and \( \mathrm{K}_{2} \) is closed (order is important).
\( \mathrm{P} \) [Take \( \mathrm{Q}_{1}{ }^{\prime} \) and \( \mathrm{Q}_{2}{ }^{\prime} \) as charges on \( \mathrm{C}_{1} \) and \( \mathrm{C}_{2} \) and \( V_{1} \) and \( V_{2} \) as voltage

W respectively.]
Then
(a) charge on \( C_{1} \) gets redistributed such that \( V_{1}=V_{2} \)
(b) charge on \( C_{1} \) gets redistributed such that \( Q_{1}{ }^{\prime}=Q_{2}{ }^{\prime} \)
(c) charge on \( C_{1} \) gets redistributed such that \( C_{1} V_{1}+C_{2} V_{2}=C_{1} E \)
(d) charge on \( C_{1} \) gets redistributed such that \( Q_{1}{ }^{\prime}+Q_{2}{ }^{\prime}=Q \)
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