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In the following reaction sequence, the amount of \( D \) (in gram) formed from 10 moles of acetophenone is .......
\( \mathrm{P} \)
(Atomic weights in \( \mathrm{g} \mathrm{mol}^{-1}: \mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14 \),
W
\( \mathrm{O}=16, \mathrm{Br}=80 \). The yield \( (\%) \) corresponding to the product in each step is given in the parenthesis)
\( \underset{\mathrm{H}_{3} \mathrm{O}^{+}}{\stackrel{\mathrm{NaOBr}}{\longrightarrow}} A \underset{(60 \%)}{\stackrel{\mathrm{NH}_{3}, \Delta}{\longrightarrow}} B \underset{(50 \%)}{\stackrel{\mathrm{Br}_{2} / \mathrm{KOH}}{\longrightarrow}} C \)
\( \stackrel{\mathrm{Br} \mathrm{B}_{2}(3 \text { equivalent })}{\mathrm{AcOH}} D \)
(100\%)
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