\( \int_{1}^{\infty}\left(e^{x+1}+e^{3-x}\right)^{-1} d x \quad \) ...
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\( \int_{1}^{\infty}\left(e^{x+1}+e^{3-x}\right)^{-1} d x \quad \) is equal to
\( \mathrm{P}^{16: 4} \)
WV
(1) \( \frac{\pi}{4 e^{2}} \)
(2) \( \frac{\pi}{4 e} \)
(3) \( \frac{\pi}{2 e^{2}} \)
(4) \( \frac{\pi}{2 e} \)
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