\( \int \frac{4 e^{x}+6 e^{-x}}{9 e^{x}-4 e^{-x}} d x \) equals....
\( \int \frac{4 e^{x}+6 e^{-x}}{9 e^{x}-4 e^{-x}} d x \) equals
\( \mathrm{P} \)
(1) \( -\frac{19}{36} x+\frac{35}{36} \log \left(9 e^{x}-4 e^{-x}\right)+c \)
(2) \( -\frac{3}{2} x+\frac{35}{36} \log \left(9 e^{2 x}-4\right)+c \)
(3) \( \frac{4}{9} x+\frac{70}{9} \int \frac{d x}{9 e^{2 x}-4}+c \)
(4) \( \frac{4}{9} x-\frac{70}{9} \int \frac{d x}{9 e^{2 x}-4}+c \)
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