Intersection of Two Arrays II | 2 Approaches | Easy Explanations | Leetcode 350 | codestorywithMIK
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This is the 45th Video of our Playlist "Leetcode Easy : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a good practice problem : Intersection of Two Arrays II | 2 Approaches | Easy Explanations | Leetcode 350 | codestorywithMIK
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Problem Name : Intersection of Two Arrays II | 2 Approaches | Easy Explanations | Leetcode 350 | codestorywithMIK
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Summary :
Approach 1: Using Hash Map
Time Complexity: O(n) Space Complexity: O(n)
Hash Map for Counting Elements:
Traverse the first array (nums1) and use an unordered_map (or HashMap in Java) to count the occurrences of each element.
Intersection Calculation:
Traverse the second array (nums2).
For each element in nums2, check if it exists in the map with a count greater than zero.
If it exists, add it to the result list and decrement its count in the map.
Advantages:
Efficient in terms of both time and space for large arrays with many duplicate elements.
Approach 2: Using Sorting and Two Pointers
Time Complexity: O(n log n) Space Complexity: O(n)
Sort Both Arrays:
Sort both input arrays (nums1 and nums2).
Two-Pointer Technique:
Use two pointers to traverse the sorted arrays.
If elements at both pointers are equal, add the element to the result list and increment both pointers.
If the element in nums1 is smaller, increment the pointer for nums1.
If the element in nums2 is smaller, increment the pointer for nums2.
Advantages:
Simple and easy to understand.
Efficient when the arrays are already sorted or nearly sorted.
Comparison
Efficiency: The hash map approach has a linear time complexity, making it faster for large arrays. The sorting and two-pointer approach has a higher time complexity due to the sorting step.
Space: Both approaches use extra space, but the hash map approach uses additional space proportional to the number of unique elements in the first array, whereas the sorting approach uses extra space mainly for the sorted arrays.
Use Case: The hash map approach is more efficient for unsorted arrays with many duplicates, while the sorting and two-pointer approach is better for arrays that are already sorted or when space is a concern.
✨ Timelines✨
00:00 - Introduction
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