Balance a Binary Search Tree | Simple Explanation | Leetcode 1382 | codestorywithMIK
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In this video we will try to solve an extremely good problem : Balance a Binary Search Tree | Simple Explanation | Leetcode 1382 | codestorywithMIK
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We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Balance a Binary Search Tree | Simple Explanation | Leetcode 1382 | codestorywithMIK
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Summary :
In-Order Traversal:
Perform an in-order traversal of the given binary search tree (BST).
Store the values in a list to get a sorted sequence of elements.
Construct Balanced BST:
Use the sorted list to construct a balanced BST.
Recursively choose the middle element of the current subarray as the root to ensure the tree remains balanced.
Assign the left half of the list to the left subtree and the right half to the right subtree.
Rebuild the Tree:
Start the process from the entire range of the list (from 0 to the size of the list minus one).
The recursive construction ensures that the resulting tree is height-balanced.
Benefits:
The in-order traversal ensures that the elements are sorted, leveraging the properties of a BST.
Recursively choosing the middle element ensures the tree is as balanced as possible, minimizing the height.
✨ Timelines✨
00:00 - Introduction
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