Let \( f(x)=2 \tan ^{-1} x=\left\{\begin{array}{ll}\cos ^{-1}\left(... VIDEO
Let \( f(x)=2 \tan ^{-1} x=\left\{\begin{array}{ll}\cos ^{-1}\left(\frac{1-x^{2}}{1+x^{2}}\right), & x \geq 0 \\ -\cos ^{-1}\left(\frac{1-x^{2}}{1+x^{2}}\right), & x0\end{array}\right. \)
\( \mathrm{P} \)
W
The function \( f(x) \) is continuous everywhere but not differentiable at \( x \) equals to
(a) 1
(b) -1
(c) 0
(d) \( \frac{1}{\sqrt{2}} \)
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