Let \( I_{1}=\int_{0}^{\pi / 4} e^{x^{2}} d x, I_{2}=\int_{0}^{\pi / 4} e^{x} d x, I_{3}=\int_{0...
Let \( I_{1}=\int_{0}^{\pi / 4} e^{x^{2}} d x, I_{2}=\int_{0}^{\pi / 4} e^{x} d x, I_{3}=\int_{0}^{\pi / 4} e^{x^{2}} \cdot \cos x d x, I_{4}=\int_{0}^{\pi / 4} e^{x^{2}} \cdot \sin x d x \) then
\( \mathrm{P} \)
(A) \( \quad I_{1}I_{2}I_{3}I_{4} \)
(B) \( I_{2}I_{3}I_{4}I_{1} \)
W.
(C) \( I_{3}I_{4}I_{1}I_{2} \)
(D) \( I_{2}I_{1}I_{3}I_{4} \)
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