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Let \( x, y z \) be three natural numbers such that \( y \) has 1 at its unit's place and \( z \) has 0 at its unit's place. Let
\[
\Delta=\left|\begin{array}{lll}
x & 4 & 1 \\
y & 0 & 1 \\
z & 1 & 0
\end{array}\right|
\]
If \( (\Delta+2) \) is divisible by 10 , then the digit at the unit's place of \( x \) is
(a) 1
(b) 2
(c) 8
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