Magnetic force on a charged particle is given by \( \vec{F}_{m}=q(\vec{v} \times \vec{B}) \) and...
0Magnetic force on a charged particle is given by \( \vec{F}_{m}=q(\vec{v} \times \vec{B}) \) and electrostatic force \( \vec{F}_{e}=q \vec{E} \). A particle having charge \( q=1 C \) and mass \( 1 \mathrm{~kg} \) is released from rest at origin. There are electric and magnetic fields given by \( \vec{E}=(10 \hat{i}) \mathrm{N} / \mathrm{C} \) for \( x=1.8 \mathrm{~m} \) and \( \vec{B}=-(5 \hat{k}) \mathrm{T} \) for \( 1.8 \mathrm{~m} \leq x \leq 2.4 \mathrm{~m} \).
A screen is placed parallel to \( y-z \) plane at \( x=3 \mathrm{~m} \). Neglect gravity forces.
\( y \)-coordinate of particle where it collides with screen (in meters) is
(1) \( \frac{0.6(\sqrt{3}-1)}{\sqrt{3}} \)
(2) \( \frac{0.6(\sqrt{3}+1)}{\sqrt{3}} \)
(3) \( 1.2(\sqrt{3}+1) \)
(4) \( \frac{1.2(\sqrt{3}-1)}{\sqrt{3}} \)
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