Make String a Subsequence Using Cyclic Increments | Similar Problem |Leetcode 2825 |codestorywithMIK
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This is the 51st Video of our Playlist "Strings" by codestorywithMIK
In this video we will try to solve an easy string problem : Make String a Subsequence Using Cyclic Increments | Similar Problem | Leetcode 2825 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Make String a Subsequence Using Cyclic Increments | Similar Problem | Leetcode 2825 | codestorywithMIK
Company Tags : will update later
My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/strings/Make String a Subsequence Using Cyclic Increments.cpp
Leetcode Link : https://leetcode.com/problems/make-string-a-subsequence-using-cyclic-increments/description/
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Summary :
The solution checks if str2 can be made a subsequence of str1 by performing a cyclic increment operation on characters of str1 at most once. The approach involves:
Two-Pointer Technique:
We use two pointers i (for str1) and j (for str2), both initialized to zero.
Character Matching:
We iterate through both strings and check if the current character of str1 can match the current character of str2 based on the following conditions:
The characters are already equal (str1[i] == str2[j]).
Incrementing str1[i] by one makes it equal to str2[j] (str1[i] + 1 == str2[j]).
The character z wraps around to a, which is handled by checking if str1[i] - 25 == str2[j].
Subsequence Validation:
If a match is found under any of the above conditions, we increment the pointer j to move to the next character of str2.
Result:
If we successfully match all characters of str2 (j == n), we return true. Otherwise, we return false.
Time Complexity:
O(m + n), where m is the length of str1 and n is the length of str2, as we traverse both strings linearly.
✨ Timelines✨
00:00 - Introduction
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