Make Two Arrays Equal by Reversing Subarrays | Easy | Leetcode 1460 | codestorywithMIK
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In this video we will try to solve an easy Array Problem : Make Two Arrays Equal by Reversing Subarrays | Easy | Leetcode 1460 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Make Two Arrays Equal by Reversing Subarrays | Easy | Leetcode 1460 | codestorywithMIK
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Summary :
Approach 1: Sorting
Time Complexity: O(n log n)
Space Complexity: O(1)
Description:
Both arrays (target and arr) are sorted.
The sorted arrays are then compared element by element.
If all corresponding elements in the sorted arrays are equal, the method returns true; otherwise, it returns false.
Advantages:
Simple and straightforward.
Does not require additional space beyond the input arrays.
Disadvantages:
Sorting both arrays can be less efficient for larger datasets due to O(n log n) time complexity.
Approach 2: Using HashMap
Time Complexity: O(n)
Space Complexity: O(n)
Description:
A HashMap is used to count the frequency of each element in the arr array.
The target array is then iterated through, and the frequency of each element is checked against the HashMap.
If an element in target does not exist in the HashMap or its frequency does not match, the method returns false.
If all elements match, the method returns true.
Advantages:
More efficient for large datasets as it runs in linear time.
Effectively handles cases where elements need to be compared based on frequency.
Disadvantages:
Requires additional space proportional to the number of unique elements in the arrays.
✨ Timelines✨
00:00 - Introduction
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