Spiral Matrix III | Simple Simulation | Made Easy | Leetcode 885 | codestorywithMIK
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This is the 100th Video of our Playlist "Array 1D/2D : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a very good Array Problem : Spiral Matrix III | Simple Simulation | Made Easy | Leetcode 885 | codestorywithMIK
Spiral Matrix I - • Spiral Matrix | Leetcode-54 | Amazon,...
Spiral Matrix II - • Spiral Matrix II | Leetcode-59 | Amaz...
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Spiral Matrix III | Simple Simulation | Made Easy | Leetcode 885 | codestorywithMIK
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My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Intervie...
Leetcode Link : https://leetcode.com/problems/spiral-...
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Summary :
The provided Java code implements a solution to traverse a matrix in a spiral order starting from a given cell (rStart, cStart). The algorithm uses an array of direction vectors to navigate east, south, west, and north cyclically. It dynamically adjusts the number of steps taken in each direction, increasing the step count after completing movements in the east or west directions.
Key points of the solution include:
Initialization: Set up direction vectors, a result array to store coordinates, and initial values for steps and direction.
Traversal Loop: Continue until all cells are visited, adjusting the direction and step count as needed.
Boundary Checks: Ensure that only valid grid positions are added to the result.
The time complexity is O(max(rows,cols)^2) due to the quadratic growth of steps needed to cover the grid and potential movements outside the grid boundaries.
✨ Timelines✨
00:00 - Introduction
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