Match the columns:
\begin{tabular}{|l|l|c|c|}
\hline \multicolumn{2}{|c|}{ Column - I } & \multicolumn{2}{c|}{ Column - II } \\
\hline A. & \( \begin{array}{l}\text { If } f(x) \text { is a quadratic expression in } \\
x \text { and } 6 \int_{0}^{1} f(x) d x=k f(1)+f(0)+ \\
4 f(1 / 2), \text { then } k \text { is }\end{array} \) & 1 \\
\hline B. & \( \begin{array}{l}\text { If the sum of the squares of the } \\
\text { intercepts on the axes cut off by } \\
\text { the } \operatorname{tangents} \text { to the curve } x^{1 / 3}+y^{1 / 3} \\
=a^{1 / 3}(a0)\end{array} \) & q. & 4 \\
\hline C. & \( \begin{array}{l}\text { The distance of the point on } y=x^{4} \\
+3 x^{2}+2 x \text { which is nearest to the } \\
\left.\text { at } \frac{a}{8}, \frac{a}{8}\right) \text { is } 2, \text { then a is }\end{array} \) & r. & 3 \\
\hline D. & \( \begin{array}{l}\text { If } y=2 x-1 \text { is } r, \text { then } \sqrt{5} r \text { is } \\
5|\tan x|^{3} \text { is differentiable at } x=0,2|\sin x|+a e^{|x|}+ \\
\text { then a is }\end{array} \) & s. & 2 \\
\hline
\end{tabular}
(a) \( \mathrm{A}-(\mathrm{p}), \mathrm{B}-(\mathrm{q}), \mathrm{C}-(\mathrm{p}), \mathrm{D}-(\mathrm{s}) \)
(b) \( \mathrm{A}-(\mathrm{r}), \mathrm{B}-(\mathrm{q}), \mathrm{C}-(\mathrm{p}), \mathrm{D}-(\mathrm{s}) \)
(c) \( \mathrm{A}- \) - \( \mathrm{q}), \mathrm{B}-(\mathrm{r}), \mathrm{C}-(\mathrm{p}), \mathrm{D}-(\mathrm{r}) \)
(d) \( \mathrm{A}-(\mathrm{r}), \mathrm{B}-(\mathrm{p}), \mathrm{C}-(\mathrm{q}), \mathrm{D}-(\mathrm{s}) \)
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