Match the list I and list II and select the correct answer using the codes given below the lists....
0Match the list I and list II and select the correct answer using the codes given below the lists:
\begin{tabular}{|l|l|l|l|}
\hline \multicolumn{2}{|c|}{ Column - I } & \multicolumn{2}{c|}{ Column - II } \\
\hline A. & \begin{tabular}{l}
A pair of \\
chain \\
Isomers
\end{tabular} & i. & \begin{tabular}{l}
\( \mathrm{O} \) \\
\( \mathrm{CH}_{3}-\mathrm{C}-\mathrm{CH}_{2} \mathrm{COOC}_{2} \mathrm{H}_{5} ; \) \\
\( \mathrm{OH} \) \\
\( \mathrm{CH}_{3}-\mathrm{C}=\mathrm{CHCOOC}_{2} \mathrm{H}_{5} \)
\end{tabular} \\
\hline B. & \begin{tabular}{l}
A pair of \\
position \\
isomers
\end{tabular} & ii. & \begin{tabular}{l}
\( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CHO} ; \) \\
\( \mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3} \)
\end{tabular} \\
\hline C. & \begin{tabular}{l}
A pair of \\
functional \\
Isomers
\end{tabular} & iii. & \begin{tabular}{l}
\( \mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{C} \equiv \mathrm{CH} ; \) \\
\( \mathrm{CH}_{3}-\mathrm{C}_{3} \equiv \mathrm{C}-\mathrm{CH}_{3} \)
\end{tabular} \\
\hline D. & \begin{tabular}{l}
A pair of \\
tautomers
\end{tabular} & iv. & \begin{tabular}{l}
\( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} ; \) \\
\( \mathrm{CH}_{3}-\mathrm{CH}_{3}-\mathrm{CH}_{3} \) \\
\( \mid \) \\
\( \mathrm{CH}_{3} \)
\end{tabular} \\
\hline
\end{tabular}
\( \mathrm{P} \)
\begin{tabular}{|l|l|l|l|}
\hline \multicolumn{2}{|c|}{ Column-I } & \multicolumn{2}{c|}{ Column - II } \\
\hline A. & \begin{tabular}{l}
A pair of \\
chain \\
Isomers
\end{tabular} & i. & \begin{tabular}{l}
\( \mathrm{O} \) \\
\( \mathrm{CH}_{3}-\mathrm{C}-\mathrm{CH}_{2} \mathrm{COOC}_{2} \mathrm{H}_{5} ; \) \\
\( \mathrm{OH} \) \\
\( \mathrm{CH}_{3}-\mathrm{C}=\mathrm{CHCOOC}_{2} \mathrm{H}_{5} \)
\end{tabular} \\
\hline B. & \begin{tabular}{l}
A pair of \\
position \\
isomers
\end{tabular} & ii. & \begin{tabular}{l}
\( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CHO} ; \) \\
\( \mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3} \)
\end{tabular} \\
\hline C. & \begin{tabular}{l}
A pair of \\
functional \\
Isomers
\end{tabular} & iii. & \begin{tabular}{l}
\( \mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{C} \equiv \mathrm{CH} ; \) \\
\( \mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3} \)
\end{tabular} \\
\hline D. & \begin{tabular}{l}
A pair of \\
tautomers
\end{tabular} & iv. & \begin{tabular}{l}
\( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} ; \) \\
\( \mathrm{CH}_{3}-\mathrm{CH}_{3}-\mathrm{CH}_{3} \) \\
\( \mathrm{CH}_{3} \)
\end{tabular} \\
\hline
\end{tabular}
\begin{tabular}{lllll}
& A & B & C & D \\
(1) & i & ii & iii & iv \\
(2). & iv & iii & ii & i \\
(3) & ii & iv & i & iii \\
(4) & iii & i & iv & ii
\end{tabular}
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