\( \mathrm{E}^{\circ} \) for the reaction, \( \mathrm{Fe}_{(\mathrm{s})}+\mathrm{Zn}_{(\mathrm{a...

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\( \mathrm{E}^{\circ} \) for the reaction, \( \mathrm{Fe}_{(\mathrm{s})}+\mathrm{Zn}_{(\mathrm{aq})}^{2+} \rightarrow \mathrm{Zn}_{(\mathrm{s})}+\mathrm{Fe}_{(\mathrm{aq})}^{2+} \) is \( -0.35 \mathrm{~V} \). The given cell reaction is
(A) spontaneous
(B) non-spontaneous
(C) in equilibrium
(D) cant say anything
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