\( \mathrm{Fe}+ \) conc. \( \mathrm{HNO}_{3} \longrightarrow X \)
\( (80 \%) \)
Then \( X \) wil...
\( \mathrm{Fe}+ \) conc. \( \mathrm{HNO}_{3} \longrightarrow X \)
\( (80 \%) \)
Then \( X \) will be:
(a) \( \mathrm{Fe}_{2} \mathrm{O}_{3} \)
(b) \( \mathrm{FeO} \)
(c) \( \mathrm{Fe}_{3} \mathrm{O}_{4} \)
(d) None of these
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