\( \mathrm{H}_{2} \mathrm{~S} \) is passed into \( \mathrm{BaCl}_{2...
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\( \mathrm{H}_{2} \mathrm{~S} \) is passed into \( \mathrm{BaCl}_{2} \) solution. The ppt formed
P is
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(1) \( \mathrm{BaS} \)
(2) \( \mathrm{Ba}(\mathrm{SH})_{2} \)
(3) \( \mathrm{Ba}(\mathrm{OH})_{2} \)
(4) No ppt.
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