\( \mathrm{KMnO}_{4} \) oxidizes \( \mathrm{X}^{n+} \) ion to \( \mathrm{XO}_{3}^{-} \), itself ...

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\( \mathrm{KMnO}_{4} \) oxidizes \( \mathrm{X}^{n+} \) ion to \( \mathrm{XO}_{3}^{-} \), itself changing to \( \mathrm{Mn}^{2+} \) in acid medium. \( 2.68 \times 10^{-3} \) mole of \( \mathrm{X}^{n^{+}} \)requires \( 1.61 \times 10^{-3} \) mole of \( \mathrm{MnO}_{4}^{-} \). What is the value of \( n \) ? Also calculate the atomic mass of \( \mathrm{X} \), if the weight of \( 1 \mathrm{~g} \) equivalent of \( \mathrm{XCl}_{\mathrm{n}} \) is 56 .
(b).
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