\( \mathrm{P} \) If \( I_{1}=\int_{-1}^{2} x \sin (x(1-x)) d x \) a...

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\( \mathrm{P} \)
If \( I_{1}=\int_{-1}^{2} x \sin (x(1-x)) d x \) and \( I_{2}= \) \( \int_{-1}^{2} \sin (x(1-x)) d x \), then \( \frac{I_{1}}{I_{2}} \) is equal to
(1) 2
(2) \( \frac{1}{2} \)
(3) 1
(4) \( \frac{1}{3} \)
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