\( \mathrm{PbI}_{4} \) does not exist because: (a) iodine is not a ...

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\( \mathrm{PbI}_{4} \) does not exist because:
(a) iodine is not a reactive
\( \mathrm{P} \)
(b) \( \mathrm{Pb} \) (IV) is oxidizing and \( \mathrm{I}^{-} \)is strong reducing agent
(c) \( \mathrm{Pb} \) (IV) is less stable than \( \mathrm{Pb} \) (II)
W
(d) \( \mathrm{Pb}^{4+} \) is not easily formed
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