Maximum Nesting Depth of the Parentheses | 2 Approaches | Leetcode 1614 | codestorywithMIK

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This is the 29th Video of our Playlist "Leetcode Easy".

In this video we will try to solve an easy map Problem :
Maximum Nesting Depth of the Parentheses | 2 Approaches | Leetcode 1614 | codestorywithMIK

I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.

Problem Name : Maximum Nesting Depth of the Parentheses | 2 Approaches | Leetcode 1614 | codestorywithMIK
Company Tags : will update soon
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Stack/Easy/Maximum%20Nesting%20Depth%20of%20the%20Parentheses.cpp
Leetcode Link : https://leetcode.com/problems/maximum-nesting-depth-of-the-parentheses/


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SUMMARY :
The provided code aims to find the maximum depth of nested parentheses in a given string `s`. It achieves this by iteratively scanning through each character of the string.
The approach maintains two variables: `result` and `openBrackets`.
- `result` keeps track of the maximum depth encountered so far.
- `openBrackets` counts the number of open parentheses encountered while traversing the string.
For each character in the string:
- If the character is an opening parenthesis '(', `openBrackets` is incremented.
- If the character is a closing parenthesis ')', `openBrackets` is decremented.
- At each step, `result` is updated to hold the maximum of its current value and the current value of `openBrackets`.
Finally, the function returns the `result`, which represents the maximum depth of nested parentheses encountered in the string.
This approach effectively tracks the depth of nested parentheses without requiring the use of a stack, making it more memory-efficient. It iterates through the string only once, resulting in a linear time complexity with respect to the length of the input string.

✨ Timelines✨
00:00 - Introduction
00:19 - Problem Explanation
07:42 - Approach-1
12:06 - Approach-2
14:33 - Coding it up

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