Minimum Index of a Valid Split | 2 Approaches | Leetcode 2780 | codestorywithMIK
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Hi Everyone, this is the 17th video of our Playlist "Hash Map/Set : Popular Interview Problems".In this video we will solve a very good Problem - Minimum Index of a Valid Split | 2 Approaches | Leetcode 2780 | codestorywithMIK
This will help us to revise "Boyre-Moore Algorithm"
Problem Name : Minimum Index of a Valid Split | 2 Approaches | Leetcode 2780 | codestorywithMIK
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My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/HashMap/Minimum Index of a Valid Split.cpp
Leetcode Link : https://leetcode.com/problems/minimum-index-of-a-valid-split
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Video Summary :
Approach 1: Brute Force using Two Maps
The idea here is to track the frequency of each number on both sides of a potential split point. We maintain two maps — one for the left part and one for the right. Initially, the entire array is considered the right part. As we iterate through the array, we move elements one by one from the right map to the left map, updating their counts. At each index, we check if the current number is a "dominant" element on both sides — i.e., its frequency is more than half the size of each subarray. If we find such a split point, we return it.
Approach 2: Using Majority Element Concept
This approach is optimized by first finding the majority element (an element that appears more than half the time in the whole array) using the Boyer-Moore Voting Algorithm. Once identified, we scan again to find the first index where this majority element is dominant in both the left and right subarrays. We track its cumulative count on the left side, and subtract it from the total to get the right side's count. This avoids the need for maps and significantly improves space efficiency.
✨ Timelines✨
00:00 - Introduction
0:19 - Motivation
0:36 - Problem Explanation
4:39 - Approach 1 : Brute Force to Better
15:36 - Coding Approach 1
18:38 - Approach 2 (Using Majority Element Concept)
27:13 - Recap Majority Element
30:21 - Coding Approach 2
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