Nitrobenzene reacts with \( \mathrm{Br}_{2} \) in the presence of \...

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Nitrobenzene reacts with \( \mathrm{Br}_{2} \) in the presence of \( \mathrm{FeBr}_{3} \) to give \( \mathrm{m} \)-bromonitrobenzene as the major product. Which of the following provides the best reason for the formation of \( \mathrm{m} \)-bromonitrobenzene as the major
P product :

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(A) The electron density at the meta position is greater than those at the ortho and para positions
(B) Aromaticity is lost in the \( \sigma \)-complexes formed by the attack of \( \mathrm{Br}^{+} \)at the ortho and para positioins but not at the meta position.
(C) The \( \sigma \)-complex formed by the attack of \( \mathrm{Br}^{+} \)at the meta position is the least destabilized and the most stable among the three \( \sigma \)-complexes
- (D) In the final step of regeneration of benzene ring by the loss of \( \mathrm{H}^{+} \)from the \( \sigma \)-complexes, the metaoriented \( \sigma \)-complex loses \( \mathrm{H}^{+} \)most readily
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