Numericals (Part 1) - Light: Reflection And Refraction | Class 10 Physics 2022-23
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✅ In this video,
✔️ Class: 10th
✔️ Subject: Physics
✔️ Chapter: Light: Reflection And Refraction (Chapter 10)
✔️ Topic Name: Numericals (Part 1) - Light: Reflection And Refraction | Class 10 Physics Chapter 10 (2022-23)
✔️ Topics Covered In This Video (by Vibhuti Ma'am): The YouTube description for this video topic is an introduction to the topic of light: reflection and refraction covered in the Class 10 Physics Chapter 10 for the academic year 2022-23 by Vibhuti Mam. This video provides an in-depth analysis of the topics from a numerical perspective and focuses on the techniques used to solve real-life problems related to light. This video is ideal for students studying class 10 science who want to learn more about light reflection and refraction and apply it to their daily lives.
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00:00 Introduction: Light: Reflection And Refraction
00:04 Question 1 to 10: Numerical: Chapter 10
Question. An object 4 cm in size is placed at a distance of 25.0 cm from a concave mirror of focal length 15.0 cm. Find the position, nature and height of the image.
33:15 Thank You
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Points covered in this video:-
Numericals -
Question. (a) If the image formed by a mirror for all positions of the object placed in front of, it is always diminished, erect and virtual, state the type of the mirror and also draw a ray diagram to justify your answer. Write one use such mirrors are put to and why?
Solution. (a) When the image of object for all positions in front of mirror is diminished, erect and virtual, the mirror must be convex. In this figure, A’B’ is virtual, erect and diminished image of object AB held in front of a convex mirror. A convex mirror is used as a rear view mirror by drivers of automobiles. Such a mirror has a large field of view.
(b) define the radius of curvature of spherical mirrors. Find the nature and focal length of a spherical mirror, whose radius of curvature is +24 cm.
Solution. (b) Radius of curvature of a spherical mirror is the radius of the sphere of which spherical mirror is a part.
When, R = + 24 cm
f = R/2
= +24/2
= +12 cm
The mirror is convex mirror.
Question. An object 4 cm in size is placed at a distance of 25.0 cm from a concave mirror of focal length 15.0 cm. Find the position, nature and height of the image.
Solution. Here, height of object, h1 = + 4 m
Object distance, u = -25.0 cm
Focal length of concave mirror, f = - 15.0 cm
Note that plus/minus signs area as New Cartesian Sign Conventions.
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