On an imaginary planet the acceleration due to gravity is same as t...
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On an imaginary planet the acceleration due to gravity is same as that on Earth but there is also a downward electric field
\( \mathrm{P} \) that is uniform close to the planet's surface. A ball of mass \( m \)
W carrying a charge \( q \) is thrown upward at a speed \( v \) and hits the ground after an interval \( t \), What is the magnitude of potential difference between the starting point and top point of the trajectory?
(A) \( \frac{m v}{2 q}\left(v-\frac{g t}{2}\right) \)
(B) \( \frac{m v}{q}\left(v-\frac{g t}{2}\right) \)
(C) \( \frac{m v}{2 q}(v-g t) \)
(D) \( \frac{2 m v}{q}(v-g t) \)
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