Prove that \(\frac{sin(x + y)}{sin(x - y)} = \frac{tan\ x + tan\ y}{tan\ x - tan\ y}\)...

Channel:
PW Solutions
Subscribers:
515,000
Published on ● Video Link: https://www.youtube.com/watch?v=xWK0G78rtqQ


Duration: 1:25
0 views
0

Prove that \(\frac{sin(x + y)}{sin(x - y)} = \frac{tan\ x + tan\ y}{tan\ x - tan\ y}\)...
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live



Other Videos By PW Solutions


2024-05-22If tan < 0, sin < 0, then the terminal arm of the angle lies in the quadrant...
2024-05-22The value of cos 65° sin 25° + sin 65° cos 25° is...
2024-05-22What is the value of (sin 30° + cos 60°) – (sin 60° + cos 30°)?...
2024-05-22If \(\theta\) is an acute angle of a right triangle, then the value of \(\text{sin\ }\theta\ cos\...
2024-05-22\(\frac{cos(\pi + x)cos( - x)}{sin(\pi - x)cos(\frac{\pi}{2} + x)} = cot^{2}x\)...
2024-05-22If the value of \(\theta + \varphi = \frac{\pi}{2}\ \)\(\text{sin\ }\theta = \frac{1}{2}\). What...
2024-05-22Which of the following is the correct value of \(c10{^\circ} \cdot cot20{^\circ} \cdot cot60{^\ci...
2024-05-22\(2sin^{2}\frac{3\pi}{4} + 2cos^{2}\frac{\pi}{4} = 2sec^{2}\frac{\pi}{3} = 10\)...
2024-05-22Find the value of: \(sin\ 75{^\circ}\)...
2024-05-22\(\text{si}n^{2}\frac{\pi}{6} + cos^{2}\frac{\pi}{3} - tan^{2}\frac{\pi}{2} = - \frac{1}{2}\)...
2024-05-22Prove that \(\frac{sin(x + y)}{sin(x - y)} = \frac{tan\ x + tan\ y}{tan\ x - tan\ y}\)...
2024-05-22Evaluate \(2\ sin\frac{\pi}{12}\)...
2024-05-22Prove that sin600° cos390° + cos480° sin 150° = –1....
2024-05-22Prove \(cos\ 70{^\circ} \cdot cos\ 10{^\circ} + sin\ 70{^\circ} \cdot sin\ 10{^\circ} = \frac{1}...
2024-05-22What is the value of tan(–1215°)?...
2024-05-22What is the value of sin 150°?...
2024-05-22What is the value of cos(–210°)?...
2024-05-22The incorrect statement is...
2024-05-22Prove that: cos(\(\pi\)/8) + cos(3\(\pi\)/8) + cos(5\(\pi\)/8) + cos(7\(\pi\)/8) = 0...
2024-05-22If A, B, C are the angles of triangle, show that; sin(A + B) = sinC...
2024-05-22Find the value of A if sin3A = cosA....