Prove that \[\sqrt{\frac{1-\sin \theta}{1+\sin \theta}}=\left\{\begin{array}{l}\sec \theta-\tan ...
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0Prove that
\[\sqrt{\frac{1-\sin \theta}{1+\sin \theta}}=\left\{\begin{array}{l}\sec \theta-\tan \theta, \text { if }-\frac{\pi}{2}<\theta<\frac{\pi}{2} \\-\sec \theta+\tan \theta, \text { if } \frac{\pi}{2}<\theta<\frac{3 \pi}{2}\end{array}\right.\]
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