Reaction of \(BeCl _2\) with \(LiAlH _4\) gives:(A) \(AlCl _3\)(B) \(BeH _2\)(C) \(LiH\)(D) \(Li....
Reaction of \(BeCl _2\) with \(LiAlH _4\) gives:(A) \(AlCl _3\)(B) \(BeH _2\)(C) \(LiH\)(D) \(LiCl\)(E) \(BeAlH _4\)
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