The angle of elevation of a stationery cloud from a point \( 2500 \mathrm{~m} \) above a lake is...

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The angle of elevation of a stationery cloud from a point \( 2500 \mathrm{~m} \) above a lake is \( 15^{\circ} \) and the angle of depression of its reflection in the lake is \( 45^{\circ} \). What is the height of the cloud above the lake level?
(Use \( \tan 15^{\circ}=0.268 \) )
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