The area of hysteresis loop of a material is equivalent \( \mathrm{...
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The area of hysteresis loop of a material is equivalent
\( \mathrm{P} \) to 250 joule. When \( 10 \mathrm{~kg} \) material is magnetised by
W an alternating field of \( 50 \mathrm{~Hz} \) then energy lost in one hour will be (density of material is \( 7.5 \mathrm{gm} / \mathrm{cm}^{3} \) )
(1) \( 6 \times 10^{4} \mathrm{~J} \)
(2) \( 6 \times 10^{4} \mathrm{erg} \)
(3) \( 3 \times 10^{2} \mathrm{~J} \)
(4) \( 3 \times 10^{2} \operatorname{erg} 3 \)
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