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The correct order of reducing power of halide ions is:
(A) \( \mathrm{Cl}^{-}\mathrm{Br}^{-}\mathrm{I}^{-}\mathrm{F}^{-} \)
(B) \( \mathrm{Cl}^{-}\mathrm{I}^{-}\mathrm{Br}^{-}\mathrm{F}^{-} \)
(C) \( \mathrm{Br}^{-}\mathrm{Cl}^{-}\mathrm{I}^{-}\mathrm{F} \)
(D) \( \mathrm{I}^{-}\mathrm{Br}^{-}\mathrm{Cl}^{-}\mathrm{F}^{-} \)
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