The current \( I \) through a rod of a certain metallic oxide is given by \( I=0.2 \mathrm{~V}^{...

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The current \( I \) through a rod of a certain metallic oxide is given by \( I=0.2 \mathrm{~V}^{5 / 2} \), where \( V \) is the potential difference across it. The rod is connected in series with a resistance to a \( 6 \mathrm{~V} \) battery of negligible internal resistance. What value should the series resistance have so that
(i) The current in the circuit is 0.44
(ii) The power dissipated in the rod is twice that dissipated in the resistance.
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